Update Data In Search Dropdown

Yii 1.1 General Discussion
1

Hello,

I’m using the standard yii code for searching and updating a yii grid view:




$('.search-form form').submit(function(){

	$('#item-grid').yiiGridView('update', {

		data: $(this).serialize()

	});

	return false;

});

The search form consists of two dropdown fields. The problem: The content of dropdown two depend on the selected value in dropdown one.

I implemented this in php, but the problem is, that the piece of jquery code above updates just the grid view. Is there a possibility to also update the search form? The ajax calls gets the whole html code, so I guess this is possible.

Any ideas?

2

Hi,

In search method , you should set the value which has been selected previously…

Then it will be selected on your next call :)

3

hi,

In your grid view use filer …




 

$this->widget('zii.widgets.grid.CGridView', array( 

	'itemsCssClass' => ' ', 

	'dataProvider'=>$model->search(), 

	'filter'=>$model, 

	'id'=>'user-grid', 

	'columns'=>array(

//your filds


));

$this->endWidget();

and in ur controller’s action just do this…




public function actionActionName()

	{

			$dataProvider=new CActiveDataProvider('Your_Model',array(

														'sort'=>array(

														'defaultOrder'=>'date_created DESC',

)

)

);

			

		$model=new YourModel('search');

		$model->unsetAttributes();  // clear any default values

		if(isset($_GET['YourModel']))

			$model->attributes=$_GET['YourModel'];

		

		

		$this->render('index',array(

			'dataProvider'=>$dataProvider,'model'=>$model,

		));

		

	}