如何执行纯的sql

我用的sql:

select sum(if(starttime>‘09:00:00’,1,0)) as late,

sum(if(endtime<‘18:00:00’,1,0)) as early

from present where userid=115 and date between ‘2009-12-1’ and ‘2009-12-31’




$db = Yii::app()->db; //you have to define db connection in config/main.php

$sql = "select sum(if(starttime>'09:00:00',1,0)) as late,

  sum(if(endtime<'18:00:00',1,0)) as early         

from present where userid=:userid and date between :date_start and :date_end"

$results = $db->createCommand($sql)->query(array(

  ':userid' => 115,':date_start'=>'2009-12-1',':date_end'=>'2009-12-31',

));

foreach($results as $result){

  echo $result['late']," and ",$result['early']," \n";

}



如果觉得不适应还可以用下面的方式:


$sql = "select sum(if(starttime>'09:00:00',1,0)) as late,

  sum(if(endtime<'18:00:00',1,0)) as early         

from present where userid=115 and date between '2009-12-1' and '2009-12-31'"

$results = $db->createCommand($sql)->query();

foreach($results as $result){

  echo $result['late']," and ",$result['early']," \n";

}

就是不绑定参数,不过还是建议采用楼上的方式,防止SQL注入。





			$db = Yii::app()->db;

			$sql ="select url_info.id,url_info.url_name,url_info.cid,GROUP_CONCAT(tags_info.tag_name) AS tag_ids,url_info.status,category.category_name from url_info,category,tags_info where 1 ".$condition." group by url_info.id order by url_info.id desc limit 0,50;";

			$results = $db->createCommand($sql)->query($params);

			foreach($results as $result){

				$dataProvider=$result;

				}