renderPartial ???

Yii 1.1 General Discussion
1

Hello, all I’m trying to do is display a view from one or more models (B,C,D) in another view (A). So I’m on Page A, and I want to display the index pages of B, C, and D. How would I do this? I tried something like the following on the view.php page for A:


$this->renderPartial('//B/index')

but I get “The ‘dataProvider’ property cannot be empty.” So then I tried adding dataProvider:


$dataProvider=new CActiveDataProvider('B');

                $this->renderPartial('index',array(

                        'dataProvider'=>$dataProvider,

                                       ),false,true);

But that gives me: “B.xxxx is not defined”, since it’s trying to access A’s properties. I can’t really find any examples on this that work for me. Any help is appreciated, thanks.

2

You can do only the render partial, you should copy all the code of the controller, prepare the model and then do the render partial.

Anyway is a quite bad practice to render a view of another model, if you need a piece of code to be reused is much better to create a widget.

3

So the best way to put in multiple views from a different controller is to create widgets? Thanks.

4

Don’t do it that way, use path aliases (this will render index.php view of B model)




$this->renderPartial('app.views.B.index');

Now, do you need to set a variable in there or a model?




// assuming you have a $model variable in the view and

// $model is a working model

$this->renderPartial('app.views.B.index',array('model'=>$model));

Do you wish to display that on another view?




$content = $this->renderPartial('app.views.C.index', array('variablename'=>$whatever),true);


// I am going to display $content into another view


$this->render('myview',array('BCONTENT'=>$content));

*** I totally agree with Zac’s comment, I highly recommend you that you do not use the view of another model, create another view (I have one in protected/views/global/messages.php that I use to display custom ajax Error messages: $this->renderPartial(‘app.views.global.messages’,array(‘type’=>‘error’,‘message’=>‘My error’));

Hope it helps

5

Hello, @Antonio Ramirez ::) im really grateful for the explanation, i actually needed this ;) ;)

6

Pleasure…

7

I want to add task/admin in site/index view.

I have done like this


$this->renderPartial('application.views.task.admin',array('model'=>$model),true);

It’s working.

But, In task/admin, below code gives error "SiteController cannot find the requested view "_search". "


$this->renderPartial('_search',array(

	'model'=>$model,

));

So i have changed it to (In /task/admin)


$this->renderPartial('//task/_search',array(

	'model'=>$model,

));

So I want to know that, Is this proper way to do it?

My admin view edit, view, delete link are current controller link

e.g. i have added /task/admin in site/index so links are

Edit :: urltoapplication/site/update/5

View :: urltoapplication/site/5

how to change them to task controller?