Render another view's index within a create/update form view

Yii 2.0 General Discussions
1

I have an index that call a typical create/update view.

Within these, the _form uses bootstrap Tabs, the 1st one renders the views ActiveForm, but on the 2nd tab I need to render the index for another related view.

As such, I used

this->render(…)

and it does display.

My issue is if I try to filter the data, no matter what I try in save the main form and closes, or render the main form on the 2nd tab instead of reloading the referenced index view. How do I get pjax to work with the 2nd view?

2

Hi,
Have you tried using redirect instead of render? Because render will display the view, but maybe you’re missing some data provided by the controller. So if you call the second actionIndex using redirect it will load the needed data and, after that, render the second index view. Without seeing your code, that’s the first thing I would try.
Regards!

3

I can post any code you want, I just did not want to inundate the initial post with a ton of code.

I’ll give that a try and post back.

4

No prob. Just try instead of calling directly the view like this:
$this->render(‘otherControllerView’, [$params])
Try calling the action in the other controller, like:
$this->redirect([otherController/action, $params])

5

It gives me a

Calling unknown method: yii\web\View::redirect()

I tried using

Yii::$app->response->redirect(Url::to(['site/view'], true));

Yii::$app->response->redirect('site/view', 302, false);

but then it replaces the content completely with the redirected controller view which isn’t what I want.

I’m wanting the Create/Update view as normally displayed and then on another tab I want to display the index view of another controller.

6

I’m testing

$controller = Yii::$app->createController(‘controller-name/action-name’)[0];
$controller->runAction(‘action-name’, [‘renderPartial’ => true])

It appears to be working but I have to do some serious testing to be 100% sure this is the correct approach to use.