Preg Replace String To Renderpartial

Yii 1.1 General Discussion
1

Hi there Yii,

I have a situation where I have to convert a certain string within a string to be renderPartial-ed.

For example:


// not actual code, just to represent the concept idea

$str = "The [%quick%] brown fox jumps over the [%lazy%] dog";


// I want it so that any string within [% %] is renderPartial-ed based on the string.

// In this case [%quick%] will be changed with the content of /site/quick.php

// and [%lazy%] will be changed with the content of /site/lazy.php

// but how?

// here is my code so far:


<?php 

function test($m) {

	return $this->renderPartial($m[1],array("data"=>$data));

}

$content = preg_replace_callback(

  '#\[%(.+?)%\]#', 'test', $data['page']['content']);

?>

// this gives error:

// Fatal error: Using $this when not in object context in yadayada/protected/views/site/single.php on line 11

How can I achieve this?

Please help.

2

You would need to use




Yii::app()->controller->renderPartial(...);