Link in Cgridview with variable outside $data

Yii 1.1 General Discussion
1

Hi, I have a CGridView on one of my views that uses a $model. So what I mean is that the view shows all the info from the model and the grid shows relational data. Now my question is, how do I access data from the $model that its outside of the CGridView data? here is my code:


   

$dataProvider=new CActiveDataProvider('Asignaciona', array(

                    'criteria'=>array(

                        'condition'=>'codigoal = \''.$model->Codigo.'\'',

                    ),

                ));

		

		$seccion=$model->seccion;

                

                $this->widget('zii.widgets.grid.CGridView', array(

                        'id'=>'asignacionp-grid',

                        'dataProvider'=>$dataProvider,

                        'summaryText'=>'',

                        'columns'=>array(

                                array(

                                      'class'=>'CLinkColumn',

                                      'labelExpression'=>'$data->codigom0->nombre',

                                      'urlExpression'=>'Yii::app()->createUrl("materias/view",array("id"=>$data->codigom,"codigo"=>$seccion));',

                                ),		

                        ),

                        'enablePagination'=>false,

                ));

How do I access the $seccion var?? I have tried to do it directly to the model but doesnt work either.

Thanks

2

I have the same doubt/need. Help will be appreciated twice =)

3 



'urlExpression' => 'array("materias/view", "id" => $data->codigom, "codigo" => "' . $seccion . '")',
4

Thanks kphtamas, works like a charm!