How to customize the CgridView name

Yii 1.1 General Discussion
1 

$this->widget('zii.widgets.grid.CGridView', array(

	'dataProvider'=>$dataProvider,

	'columns'=>array(

		array(

			'name' => 'id',

			'type'=>'raw',

			'value' => 'CHtml::link(CHtml::encode($data->id),array("example/view","id"=>$data->id))',

		),

		array(

			'name' => 'customusername',

			'type'=>'raw',

			'value' => 'CHtml::link(CHtml::encode($data->userid->username),array("user/admin/view","id"=>$data->userid->id))',

		),

		array(

			'name'=>'customemail',

			'type'=>'raw',

			'value'=>'CHtml::link(CHtml::encode($data->userid->email), "mailto:".$data->userid->email)',

		),

If is use username this write from the model attribute, but is use custom name this is the header name and i dont use the sort options. How to use custom name with sort options?

2

I’m not absolutely sure that I understand your question, but I think you might be looking for the “header” key:


                array(

                        'header' => 'customusername',

                        'name' => 'userid.username',

                        'type'=>'raw',

                        'value' => 'CHtml::link(CHtml::encode($data->userid->username),array("user/admin/view","id"=>$data->userid->id))',

                ),

Also, I believe there is already an "email" type that will do the formatting you want for your email attribute:

"userid.email:email:customemail"

3

It’s great.

If is use foreign table, how to sortable?


                array(

                        'header' => 'customusername',

                        'name' => 'userid.username', //is it the foreign table column and not sortable

                        'type'=>'raw',

                        'value' => 'CHtml::link(CHtml::encode($data->userid->username),array("user/admin/view","id"=>$data->userid->id))',

                ),

I find the solution. link

4

This is, if I may say, a classic wiki:

Searching and sorting by related model in CGridView

5

Hi

for foreign table

you have to use

if foreign table BELOGNS_TO

$data->foreignTableName->FieldName;

if foreign table HAS_MANY

$data->foreignTableName[0]->FieldName;

Thanks