How to create dropdown list box

International Indian
1

I have two table branch and other state. Branch table has state_id link with state table by state_id.

Two model are created for both tables. Now I want to create a dropdown list box with all state anem present in State table thru Branch model to display it in a form.

2

Hi

use

$list = CHtml::listData($models,‘State_id’, ‘State_name’);

echo CHtml::dropDownList(‘state’, $models->state_id, $list, array(‘empty’ => ‘(Select a state’));

Thanks

3

@ Pravin Gajera

Thanks for your reply.

I still have problem in getting data through “$list = CHtml::listData($models,‘State_id’, ‘State_name’);”. It is returning empty array

4

In View For Our Form Just

Instead Of textField Just Write

[color=#1C2837][size=2]echo CHtml::dropDownList(‘state’, $models->state_id,array_merge($list, array(‘empty’ => ‘(Select a state’)));[/size][/color]

5

$list=CHtml::listData(SysState::model()->findAll(), ‘state_id’, ‘state_name’); fixed my problem.

6

this works… Thanks!

7

I am new to this yii framework and Now i am working on the login page i stored the username and password in the login table and i want to retrieve these values in authenticate() which is present UserIdentity.php

my table name is login with two columns username password

my Model name is LoginForm.php

and

my register model name is Register.php

through this i stored the values into the database

my code in authentication() is

public function authenticate()

{


	$username = strtolower($this->username);


	$password = $this->password;


	$user = Register::model()->find('username=:username and password=:password', 


	array(


		':username'=>$username,


		':password'=>$password,


	));	


	


	if ($user === null)


		$this->errorCode = self::ERROR_USERNAME_INVALID;


	else 


		 return $this->errorCode == self::ERROR_NONE;


}

so please help me in retrieving these values correctly.

8

Try this :

class UserIdentity extends CUserIdentity

{

public $_id;

public function authenticate()

{


    $username=strtolower($this->username);


    $user=Register::model()->find('LOWER(username)=?',array($username));


    if($user===null)


        $this->errorCode=self::ERROR_USERNAME_INVALID;


    else if(!$user->validatePassword($this->password))


        $this->errorCode=self::ERROR_PASSWORD_INVALID;


    else


    {


        $this->_id=$user->id;


		


        $this->username=$user->username;


        $this->errorCode=self::ERROR_NONE;


    }


    return $this->errorCode==self::ERROR_NONE;


}








public function getId()


{


	return $this->_id;


}

}

9

<?php echo $form->dropDownList($addr,‘cou_id’, CHtml::listData(AccAccount::model()->findAll(‘cou_id’), ‘cou_id’, ‘cou_name’), array(‘empty’=>’–none–’)) ?>

10

hi

i want to give link in dropdown is it possible…???

i want to check email id already present in table if it is

already present then by clicking on email id i have to goto the profile whose email id is present…