How to Change labelEx Value Dynamically?

In my view i have these

	<div class="row">

		<?php echo $form->labelEx($model,'His Name'); ?>

		<?php echo $form->textField($model,'Name'); ?>

		<?php echo $form->error($model,'Name'); ?>


Then i have a dropdownlist that allow user to select Male/Female. When user select Female i need the labelEx above to change to ‘Her Name’.

How should i do that? (without refreshing the page)

use ajax on select of dropdown…

<?php echo CHtml::dropDownList('country','',array(),array('prompt'=>'Select',

	'ajax' => array(


	'url'=>CController::createUrl('registration/region'), //create an action and echo his/her

	'update'=>'#region_id', //id to refresh, his/her



	))); ?>

Hi Rajith

How do i get ‘#region_id’ from <?php echo $form->labelEx($model,‘His Name’); ?>

Also for my action in controller how do i check the value of selected sex and then echo accordingly?

	public function actionChangeSex()


		echo "Her";


give that id to a div or to that label

the value selected will get as $_POST[ur model name] in the controller.

Hmm… my action doesn’t get call at all :(

	echo $form->dropDownList($model, 'Sex', $SexArray,


        'ajax' => array(






I manually call ChangeSex at browser and it display correct value. The dropdownlist doensn’t call the ajax post somehow…

use firebug- console in firefox…u can see the post error… check it… or controller path issue.

Ajax… for this?

Come on … its like trying to kill an insect with an anti-aircraft missile - it would work, but the question is would it be worth it :).

In this case - no.

Ajax is necessary only when updating with dynamic content, which is not available to the client. In this case you already know the content:

about 4 lines of JS code

I agree this is how it should be done but i am still trying to figure out how to incorporate this into yii, finding the right place to insert the script and etc.

Thank you all for the advices.