Gridview In Another View.

Yii 1.1 General Discussion
1

Hello,

I was wondering if was possible, to use the Gridview with the data from a model. in a view without that corresponding model.

In fact I already tried it though. but all I can’t get to work is the search function (not the advanced search)

Although the filtering works.

ALl information would be welcome, (I use the extension of Bootstrap, But I doubt this would make much difference)

Thx for your time : )

2

in order to work the searching function you should set the filter property of the gridview to the model that provides data.

3

Now this is the code I use in my Gridview:


<?php $this->widget('bootstrap.widgets.TbGridView',array(

	'id'=>'repairs-grid',

	'dataProvider'=> Repairs::model()->search(),

	'filter'=>  Repairs::model(),

	'columns'=>array(

Now the gridview does show all the data it should, only the search boxes that each column has. that’s where my problem lies. I think they don’t works cause they don’t reach the DBcriteria. is there anny way to fix this?

4

first of all you must create the object for Repairs model under search scenario in your action and then pass the model to your view like this




//1. in action

actionGrid()

{

$model= new Repairs('search');

$this->render('myView',array('model'=>$model);

}


//2. in view

$this -> widget( 'bootstrap.widgets.TbGridView' , array(

'id' => 'repairs-grid' ,

'dataProvider' => $model-> search (),

'filter' =>$model,

'columns' =>array (

 ....

)

));
5

Thx for you fast responses, Due to illness I haven’t been able to work on my project for quite some time. but I’m all better now.

I have a few questions.

I’ve tried to use the actionGrid, if I’m correct this is supposed to be in my RepairController right?

Do I also have to add something in my model cause of this?

Then also, the $this->render(‘myview’), I don’t know what view to put in there, cause the view I want it in, does not belong to this model.

Note that, the search and all does work in the view with the corresponding model.

6

use like this




$this->render('/repairs/yourView',array('model'=>$model));

Note: repairs is a model name and yourView is your view file to render grid starting with slash(/) is must