Go To Site/index By Loging In During Registration

Hi,

I am trying to add Login and Registration on the same page. So After creating the Yii app via ./yiic webapp command, I created a User Model class through gii and generated the appropriate CRUD. I modified the “Create User” link to suite my need so that When a User inputs his credentials and presses the Join Us button,it is redirected to the site/index page. My problem is that I want the site/index page to show the logout button. I can’t see this button at this time for me to be able to logout.

How would I be able to redirect to site/index after registration so that the page appears with the logout button?

below is my UserController.php that I modified:




<?php


class UserController extends Controller

{

	/**

	 * @var string the default layout for the views. Defaults to '//layouts/column2', meaning

	 * using two-column layout. See 'protected/views/layouts/column2.php'.

	 */

	public $layout='//layouts/column2';


	/**

	 * @return array action filters

	 */

	public function filters()

	{

		return array(

			'accessControl', // perform access control for CRUD operations

			'postOnly + delete', // we only allow deletion via POST request

		);

	}


	/**

	 * Specifies the access control rules.

	 * This method is used by the 'accessControl' filter.

	 * @return array access control rules

	 */

	public function accessRules()

	{

		return array(

			array('allow',  // allow all users to perform 'index' and 'view' actions

				'actions'=>array('index','view'),

				'users'=>array('*'),

			),

			array('allow', // allow authenticated user to perform 'create' and 'update' actions

				'actions'=>array('create'),

				'users'=>array('*'),

			),

			array('allow', // allow authenticated user to perform 'create' and 'update' actions

				'actions'=>array('update'),

				'users'=>array('@'),

			),

			array('allow', // allow admin user to perform 'admin' and 'delete' actions

				'actions'=>array('admin','delete'),

				'users'=>array('admin'),

			),

			array('deny',  // deny all users

				'users'=>array('*'),

			),

		);

	}


	/**

	 * Displays a particular model.

	 * @param integer $id the ID of the model to be displayed

	 */

	public function actionView($id)

	{

		$this->render('view',array(

			'model'=>$this->loadModel($id),

		));

	}


	/**

	 * Creates a new model.

	 * If creation is successful, the browser will be redirected to the 'view' page.

	 */

	public function actionCreate()

	{

		$model=new User;


		// Uncomment the following line if AJAX validation is needed

		 $this->performAjaxValidation($model);


		if(isset($_POST['User']))

		{

			$model->attributes=$_POST['User'];

			if($model->save())

			{

				//$this->redirect(array('view','id'=>$model->user_id));

				//$this->redirect(Yii::app()->homeUrl);

                $identity=new UserIdentity($model->email,$model->password);

                $identity->authenticate();

                Yii::app()->user->login($identity,0);	

			

				$this->redirect(array('site/index'));

		    }				

				

			

		}


		$this->render('create',array( 'model'=>$model, ));

	}


	/**

	 * Updates a particular model.

	 * If update is successful, the browser will be redirected to the 'view' page.

	 * @param integer $id the ID of the model to be updated

	 */

	public function actionUpdate($id)

	{

		$model=$this->loadModel($id);


		// Uncomment the following line if AJAX validation is needed

		// $this->performAjaxValidation($model);


		if(isset($_POST['User']))

		{

			$model->attributes=$_POST['User'];

			if($model->save())

				$this->redirect(array('view','id'=>$model->user_id));

		}


		$this->render('update',array(

			'model'=>$model,

		));

	}


	/**

	 * Deletes a particular model.

	 * If deletion is successful, the browser will be redirected to the 'admin' page.

	 * @param integer $id the ID of the model to be deleted

	 */

	public function actionDelete($id)

	{

		$this->loadModel($id)->delete();


		// if AJAX request (triggered by deletion via admin grid view), we should not redirect the browser

		if(!isset($_GET['ajax']))

			$this->redirect(isset($_POST['returnUrl']) ? $_POST['returnUrl'] : array('admin'));

	}


	/**

	 * Lists all models.

	 */

	public function actionIndex()

	{

		$dataProvider=new CActiveDataProvider('User');

		$this->render('index',array(

			'dataProvider'=>$dataProvider,

		));

	}


	/**

	 * Manages all models.

	 */

	public function actionAdmin()

	{

		$model=new User('search');

		$model->unsetAttributes();  // clear any default values

		if(isset($_GET['User']))

			$model->attributes=$_GET['User'];


		$this->render('admin',array(

			'model'=>$model,

		));

	}


	/**

	 * Returns the data model based on the primary key given in the GET variable.

	 * If the data model is not found, an HTTP exception will be raised.

	 * @param integer the ID of the model to be loaded

	 */

	public function loadModel($id)

	{

		$model=User::model()->findByPk($id);

		if($model===null)

			throw new CHttpException(404,'The requested page does not exist.');

		return $model;

	}


	/**

	 * Performs the AJAX validation.

	 * @param CModel the model to be validated

	 */

	protected function performAjaxValidation($model)

	{

		if(isset($_POST['ajax']) && $_POST['ajax']==='user-form')

		{

			echo CActiveForm::validate($model);

			Yii::app()->end();

		}

	}

}



Dear Friend

You can add following two lines in

views/site/index.php




if(!Yii::app()->user->isGuest)

	echo CHtml::button("Logout",array("submit"=>array("site/logout")));



Regards.

Hi,

I tried it and it does not work. Any other suggestions?