$.fn.yiiGridView.update and callback (or success method)

Yii 1.1 General Discussion
1

Hi, all

I need to call $.fn.yiiGridView.update method with callback-function in my block of javascript code. Using ajaxAfterUpdate (when we call “$this->widget(‘zii.widgets.grid.CGridView’…”) option does not suit me.

When i do so:


$.fn.yiiGridView.update('app-list', {

        data: {

            seriesDel: [1,2,3]

        },

        success: function(data){

            alert('ok')

        }

    });

…original success method is overwritten. So it don’t work correctly. I don’t know OOP programming in JS so good, so i don’t know how do it correctly.

Please, tell me how to call $.fn.yiiGridView.update with callback function correctly.

2

it was resolved by me. options are passed to the $.ajax, so we can do next:


$.fn.yiiGridView.update('app-list', {

        data: {

            seriesDel: [1,2,3]

        },

        complete: function(jqXHR, status) {

            if (status=='success'){

                console.log(jqXHR, status)

            }

        }

    });