Hi All,
I want to have a popup containing a dropdownlist and based on what is selected,
the specific view should be rendered…
How can I do this?
Please some advice…
Hi All,
I want to have a popup containing a dropdownlist and based on what is selected,
the specific view should be rendered…
How can I do this?
Please some advice…
So in the popup I just want to have one dropdownlist with the values from one table…
How can I do this in Yii?
<html>
<head>
<title>LIGHTBOX EXAMPLE</title>
<style>
.black_overlay{
display: none;
position: absolute;
top: 0%;
left: 0%;
width: 100%;
height: 100%;
background-color: black;
z-index:1001;
-moz-opacity: 0.8;
opacity:.80;
filter: alpha(opacity=80);
}
.white_content {
display: none;
position: absolute;
top: 25%;
left: 25%;
width: 50%;
height: 50%;
padding: 16px;
border: 16px solid orange;
background-color: white;
z-index:1002;
overflow: auto;
}
</style>
</head>
<body>
<p>This is the main content. To display a lightbox click <a href = "javascript:void(0)" onclick = "document.getElementById('light').style.display='block';document.getElementById('fade').style.display='block'">here</a></p>
<div id="light" class="white_content">This is the lightbox content. <a href = "javascript:void(0)" onclick = "document.getElementById('light').style.display='none';document.getElementById('fade').style.display='none'">Close</a>
<div class="form">
<?php $form=$this->beginWidget('CActiveForm'); ?>
<div class="row">
<?php echo $form->labelEx($model,'attribute'); ?>
<?php echo $form->dropDownList($model,'attribute', CHtml::listData(Category::model()->findAll(), 'category_id', 'category_name')); ?>
<?php echo $form->error($model,'attribute'); ?>
</div>
<div class="row buttons">
<?php
echo CHtml::submitButton("Submit");
?>
</div>
<?php $this->endWidget(); ?>
</div>
</div>
<div id="fade" class="black_overlay"></div>
</body>
Thank you moginn
It works
I need to open a popup window on selection of dropdown option in dropdownlist in order to collect input.