Creating Model By Holding Name In String $Var

[ognistyi]

Hello,

I try to create a model instance using string variable to store his name:

use common\models\User;   //  <<< !!!

// ----------


$model_name = 'User';

$model = $model_name::find()->all(); //  PHP Fatal Error 'yii\base\ErrorException' with message 'Class 'User' not found'

But next code works fine:

$model = User::find()->all();

ok, I changed the code to:

$model_name = 'common\models\User';

and now, code works fine.

But, why works -

User::find()->all();

and don’t worked -

$model_name = 'User';  $model_name::find()->all();

Thanks!

[alirz23 (Ali Raza)]

my question is why would you do that in the first place?

[softark]

Importing is performed at compile-time, and so does not affect dynamic class, function or constant names.

Example #3 Importing and dynamic names

<?php

use My\Full\Classname as Another, My\Full\NSname;


$obj = new Another; // instantiates object of class My\Full\Classname

$a = 'Another';

$obj = new $a;      // instantiates object of class Another

?>

http://php.net/manual/en/language.namespaces.importing.php

[EDIT]

User::find()->all();

In compile-time, it gets compiled as

common\models\User::find()->all();

But a string variable will not be "compiled". It just gets interpreted in run-time.

$model_name = 'User';

$model_name::find()->all();

// same as User::find()->all() ... tries to call the global User::find()->all()

[ognistyi]

@softark, Thanks