Creating 2 Save Actions In The Same Controller?

Yii 1.1 General Discussion
1

Hi all,

I am building a data entry application where one particular area is quite large and there is a lot of information to enter.

Due to the way in which the staff enter the information it has become a requirement that they need have 2 save buttons on the CRUD create & update pages, one for ‘Save’ and one for ‘Save and close’. The save button will create/update the record and keep the user on the same page and the other will create/update the record but then re-direct them back to the index page where I have a Grid View of all records.

My action method in the controller currently looks like this:


public function actionUpdate($id)

{

		$model=$this->loadModel($id);

		

		$this->pageTitle = "Property #". $id;


		// Uncomment the following line if AJAX validation is needed

		// $this->performAjaxValidation($model);


		if(isset($_POST['Properties']))

		{

			$model->attributes=$_POST['Properties'];

			if($model->save())

				$this->redirect(array('update','id'=>$model->pr_id));

		}


		$this->render('update',array(

			'model'=>$model,

		));

}

As you can see above when a user updates a record it currently keeps them on the same page so that they are ready to amend more fields.

I am guessing that I need to do something around the $model->save() property but I can’t work out how to separate the save actions and put them into a button.

Has anyone managed to do this and can anyone be kind enough to point me in the correct direction?

Many thanks

2

Did you try to set js redirect on success in the submit button ? I didnt try it but maybe it will help.

3

In case of submit buttons give them the same name but different values so that you can check value with something like




Yii::app()->request->getPost('button_name'); // should be equivalent to $_POST['your-form-name']['button_name'] I think

// if you have problems check the posted data in your controller with

//CVarDumper::dump($_POST);

Dependent on this button value you can stay on same site or redirect to index page.

4

Thanks for the suggestions guys.

I actually worked out another way of doing this. I don’t know whether it is properly Yii-correct but it seems to work.

Buttons in the view…


<?php echo CHtml::submitButton('Save', array('name' => 'save', 'class' => 'btn btn-medium btn-primary')); ?>


<?php echo CHtml::submitButton('Save & Close', array('name' => 'saveclose', 'class' => 'btn btn-medium btn-secondary')); ?>

The Controller…


public function actionUpdate($id)

	{

		$model=$this->loadModel($id);


		// Uncomment the following line if AJAX validation is needed

		// $this->performAjaxValidation($model);


		if(isset($_POST['Properties']))

		{

			$model->attributes=$_POST['Properties'];

			if($model->save())

		

		 	if(isset($_POST['save']))

        	{

        		$this->redirect(array('update','id'=>$model->pr_id));

        	}

		

      		if(isset($_POST['saveclose']))

        	{

        		$this->redirect(array('index'));

        	}


		}


		$this->render('update',array(

			'model'=>$model,

		));

}

I hope this helps anyone else who might want to do something like this.

5

You got the idea how to do it, nice

It is another - more html clean/valid way I think - way of doing it. I could imagine that in W3C specification buttons with same names are not allowed.