Hi Guys!
Lets say we have 2 related tables for example:
user and setting
Now I want to list all users which have no settings…
With mySQL I could do it for example like this:
$sql =
'
SELECT u.* FROM user AS u
LEFT JOIN setting AS s
ON u.id = s.user_id
WHERE s.user_id IS NULL
';
$users = User::findBySql($sql)->all();
Questions are:
[list=1]
[*]Should I keep it that way?
[*]Or is there a better Yii2-way to do this?
[*]If yes: how would you solve this? (could you please give example?)
[/list]
I found for example this:
But was to dumb to get it working…
Thank you and best regards