I have an employee table (ID, SSN, name) and an assignment table. I can assign employees to locations in the assignment table. You can only see info on employees that are already at your location. If you know the SSN of the employee it is assumed that you can have access to that employee info and make an assignment.
I want the enteree to enter a SSN, Yii looks it up to see that it is valid and in the employee table, then returns the name to the _form so that the enteree can see the name and know they entered it right. And the employee_ID is available to the model. I added employee_ssn as a variable to the model.
It doesn’t seem to be calling the controller as I get no var_dump. (First problem)
Would this be the right way to display the name?
So I have my assignment form
<?php
echo $form->labelEx($model, 'employee_ssn');
echo $form->textField($model, 'employee_ssn', array(
'ajax' => array(
'type'=>'POST', //request type
'url' => CController::createUrl('getName'), //url to call.
'success'=>'js:function(data) { $("#assignment_employee_ssn").val(data); }',
)
));
echo $form->error($model, 'employee_ssn');
Controller
public function actionGetName() {
echo " Got Name <pre> "; var_dump($_POST); die;
if (!empty($_POST['ssn'])) {
$sql = 'SELECT employee_ID, CONCAT(first_name," ",last_name) as name FROM employee WHERE ssn ='.$_POST['ssn'] ;