Hi,
I’ve got this CMenu with submenu items on model3 item.
<div id="myslidemenu" class="jqueryslidemenu">
<?php $this->widget('zii.widgets.CMenu',array(
'activateParents'=>false,
'items'=>array(
array('label'=>'Home', 'url'=>array('/site/index')),
array('label'=>'model1', 'url'=>array('/model1/admin')),
array('label'=>'model2', 'url'=>array('/model2/admin')),
array('label'=>'model3', 'url'=>array('')
'items'=>array(
array('label'=>'model3-action1', 'url'=>array('model3/action1')),
array('label'=>'model3-action2', 'url'=>array('model3/action2')),
),
array('label'=>'Login', 'url'=>array('/site/login'),
array('label'=>'Logout ('.Yii::app()->user->name.')', 'url'=>array('/site/logout')
),
)); ?>
<br style="clear: left" />
</div><!-- myslidemenu -->
How can I make the parent model3 not to be URL just to open submenu with model3-action1 and model3-action2?
Now when I put mouse over model3 menu item I get current URL, even with ‘activateParents’=>false.
array('label'=>'model3', 'url'=>array(''),
When I remove ‘url’ param it works then… but item model3 loses css.
Any suggestions about this?