How Send Parameter And Check Variable In Dialog?

Yii 1.1 General Discussion
1

Hi,

I try send parameter do zii.widgets.jui.CJuiDialog e.g:





$("#dialog-animation").dialog( { my_name: 'Update' } ).dialog( 'open' );

and my dialog example:




$this->beginWidget('zii.widgets.jui.CJuiDialog', array(

    'id' => 'dialog-animation',

    'options' => array(

        'title' => 'Dialog box - Animation',

        'modal' => true,

        'autoOpen' => false,

        'height' => 'auto',

        'width' => 'auto',

        'show' => array(

            'effect' => 'blind',

            'duration' => 1000,

        ),

        'hide' => array(

            'effect' => 'explode',

            'duration' => 500,

        ),

        //przyciski

        'buttons' => array(

            'OK' => 'js:function(){alert("OK");}',

            'Anuluj' => 'js:function(){ $(this).dialog("close");}',

        ),

    ),

ok and when i try catch object my_name to variable e.g:




$my_variable = $my_name;

i see error: Undefined variable: my_name

How send correct parameter do zii.widgets.jui.CJuiDialog and print to the inside dialog?

Jarek

P.S I’m sorry, my English isn’t good.

2

You can’t pass parameter from js to php, you should make an ajax request.

Can’t you simply:


<?php $this->beginWidget('zii.widgets.jui.CJuiDialog', array('...')) ?>


Write php stuffs here <?php echo $with_params?>


<?php $this->endWidget()?>
3

Hi,

You can send the Parameter via javascript to the Controller via ajax Request and then from the Controller you can use render/renderPartial method to transfer the Parameter to View file again.Place this view file inside the cjuidialog.

This is the Simple Solution i think so,please give a try.